5sin^2x+4cosx+4=0

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Solution for 5sin^2x+4cosx+4=0 equation:


Simplifying
5sin2x + 4cosx + 4 = 0

Reorder the terms:
4 + 4cosx + 5in2sx = 0

Solving
4 + 4cosx + 5in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 4cosx + -4 + 5in2sx = 0 + -4

Reorder the terms:
4 + -4 + 4cosx + 5in2sx = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 4cosx + 5in2sx = 0 + -4
4cosx + 5in2sx = 0 + -4

Combine like terms: 0 + -4 = -4
4cosx + 5in2sx = -4

Add '-5in2sx' to each side of the equation.
4cosx + 5in2sx + -5in2sx = -4 + -5in2sx

Combine like terms: 5in2sx + -5in2sx = 0
4cosx + 0 = -4 + -5in2sx
4cosx = -4 + -5in2sx

Divide each side by '4osx'.
c = -1o-1s-1x-1 + -1.25in2o-1

Simplifying
c = -1o-1s-1x-1 + -1.25in2o-1

Reorder the terms:
c = -1.25in2o-1 + -1o-1s-1x-1

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